What is the general solution for cos^2(θ)=1-sin(θ) ?

The general solution for cos^2(θ)=1-sin(θ) is θ=2pin,θ=pi+2pin,θ= pi/2+2pin

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cos^2(θ)=1-sin(θ)

cos^{2} (θ) = 1 - sin (θ)

θ = 2 πn, θ = π + 2 πn, θ = \frac{π}{2} + 2 πn

Solution steps

cos^{2} (θ) = 1 - sin (θ)

Subtract

1 - sin (θ)

from both sides

cos^{2} (θ) - 1 + sin (θ) = 0

Rewrite using trig identities

sin (θ) - sin^{2} (θ) = 0

Solve by substitution

sin (θ) = 0, sin (θ) = 1

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

sin (θ) = 1 : θ = \frac{π}{2} + 2 πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn, θ = \frac{π}{2} + 2 πn

1 sin (3 0^{\circ}) = 1.495 sin (x)

e^{2 c o s (x) - 1} = 1

csc (θ) = - \frac{37}{12}, \frac{3 π}{2} \leq θ \leq 2 π

\frac{3}{2} = 2 \cdot 25 sin (\frac{θ}{2})

sin^{2} (x) - sin (x) - 12 = 0

What is the general solution for cos^2(θ)=1-sin(θ) ?
The general solution for cos^2(θ)=1-sin(θ) is θ=2pin,θ=pi+2pin,θ= pi/2+2pin