What is the general solution for cos(x)+(sqrt(3))/2 =0,0<= x<= 2pi ?

The general solution for cos(x)+(sqrt(3))/2 =0,0<= x<= 2pi is x=(5pi)/6 ,x=(7pi)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(x)+(sqrt(3))/2 =0,0<= x<= 2pi

cos (x) + \frac{3}{2} = 0, 0 \leq x \leq 2 π

x = \frac{5 π}{6}, x = \frac{7 π}{6}

Solution steps

cos (x) + \frac{3}{2} = 0, 0 \leq x \leq 2 π

Move

\frac{3}{2}

to the right side

cos (x) = - \frac{3}{2}

General solutions for

cos (x) = - \frac{3}{2}

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{5 π}{6}, x = \frac{7 π}{6}

sinh (x) = \frac{12}{35}

sin^{2} (x) + \frac{1}{sec ( x )} = \frac{5}{4}

2 cos (\frac{1}{5} θ) = 3

sec (θ) = - \frac{7}{13}

tan (x) = - \infty

What is the general solution for cos(x)+(sqrt(3))/2 =0,0<= x<= 2pi ?
The general solution for cos(x)+(sqrt(3))/2 =0,0<= x<= 2pi is x=(5pi)/6 ,x=(7pi)/6