What is the general solution for tan^2(θ)-tan(θ)-2=0 ?

The general solution for tan^2(θ)-tan(θ)-2=0 is θ=1.10714…+pin,θ=(3pi)/4+pin

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tan^2(θ)-tan(θ)-2=0

tan^{2} (θ) - tan (θ) - 2 = 0

θ = 1.10714 \dots + πn, θ = \frac{3 π}{4} + πn

Solution steps

tan^{2} (θ) - tan (θ) - 2 = 0

Solve by substitution

tan (θ) = 2, tan (θ) = - 1

tan (θ) = 2 : θ = arctan (2) + πn

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = arctan (2) + πn, θ = \frac{3 π}{4} + πn

Show solutions in decimal form

θ = 1.10714 \dots + πn, θ = \frac{3 π}{4} + πn

sin (x) = cos^{2} (x) - 1

tan (x) = a, tan (x + 18 0^{\circ})

cos (x) (tan (x) csc (x))^{2} - 1 = 2 cos (x)

sin (a) = \frac{4}{6}

cos (a) = 0.94

What is the general solution for tan^2(θ)-tan(θ)-2=0 ?
The general solution for tan^2(θ)-tan(θ)-2=0 is θ=1.10714…+pin,θ=(3pi)/4+pin