What is the general solution for cosh(2x)=2cosh(x)-1 ?

The general solution for cosh(2x)=2cosh(x)-1 is x=0

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cosh(2x)=2cosh(x)-1

cosh (2 x) = 2 cosh (x) - 1

x = 0

Solution steps

cosh (2 x) = 2 cosh (x) - 1

Rewrite using trig identities

\frac{e ^{2 x} + e ^{- 2 x}}{2} = 2 \cdot \frac{e ^{x} + e ^{- x}}{2} - 1

\frac{e ^{2 x} + e ^{- 2 x}}{2} = 2 \cdot \frac{e ^{x} + e ^{- x}}{2} - 1 : x = 0

x = 0

1 = \frac{3 sin ^{2} ( x )}{cos ^{2} ( x )}

4 cos (3 x) = 2

4 cos (2 x) = 4 cos^{2} (x) - 1

tan (8 b) = cot (10 b)

θ, cos (θ) = 0

What is the general solution for cosh(2x)=2cosh(x)-1 ?
The general solution for cosh(2x)=2cosh(x)-1 is x=0