What is the general solution for -3=tan^2(θ)-2-2tan(θ) ?

The general solution for -3=tan^2(θ)-2-2tan(θ) is θ= pi/4+pin

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-3=tan^2(θ)-2-2tan(θ)

- 3 = tan^{2} (θ) - 2 - 2 tan (θ)

θ = \frac{π}{4} + πn

Solution steps

- 3 = tan^{2} (θ) - 2 - 2 tan (θ)

Switch sides

tan^{2} (θ) - 2 - 2 tan (θ) = - 3

Solve by substitution

tan (θ) = 1

tan (θ) = 1 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = \frac{π}{4} + πn

- 2 cos^{2} (x) - 9 sin (x) - 3 = 0

sin (2 x) = - \frac{2 6}{7}

tan (6 x) - 3 tan (3 x) = 0

sin (a) = \frac{2}{5}

cos^{2} (θ) - cos (θ) - 1 = 0

What is the general solution for -3=tan^2(θ)-2-2tan(θ) ?
The general solution for -3=tan^2(θ)-2-2tan(θ) is θ= pi/4+pin