What is the general solution for sin(3x-pi/5)=0-1 ?

The general solution for sin(3x-pi/5)=0-1 is x=(2pin)/3+(17pi)/(30)

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sin(3x-pi/5)=0-1

sin (3 x - \frac{π}{5}) = 0 - 1

x = \frac{2 πn}{3} + \frac{17 π}{30}

Solution steps

sin (3 x - \frac{π}{5}) = 0 - 1

Subtract the numbers:

0 - 1 = - 1

sin (3 x - \frac{π}{5}) = - 1

General solutions for

sin (3 x - \frac{π}{5}) = - 1

3 x - \frac{π}{5} = \frac{3 π}{2} + 2 πn

Solve

3 x - \frac{π}{5} = \frac{3 π}{2} + 2 πn : x = \frac{2 πn}{3} + \frac{17 π}{30}

x = \frac{2 πn}{3} + \frac{17 π}{30}

2 + sin (3 θ) = 3 - sin (3 θ)

sin (2 x) = - cos (3 x) + sin (4 x)

sin (x + \frac{π}{2}) = - cos (x)

sin (x) = (\frac{3}{5})

x, sin^{2} (x) = cos^{2} (x)

What is the general solution for sin(3x-pi/5)=0-1 ?
The general solution for sin(3x-pi/5)=0-1 is x=(2pin)/3+(17pi)/(30)