What is the general solution for solvefor x,sin^2(x)=cos^2(x) ?

The general solution for solvefor x,sin^2(x)=cos^2(x) is x= pi/4+pin,x=(3pi)/4+pin

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solvefor x,sin^2(x)=cos^2(x)

solve for

x, sin^{2} (x) = cos^{2} (x)

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

sin^{2} (x) = cos^{2} (x)

Subtract

cos^{2} (x)

from both sides

sin^{2} (x) - cos^{2} (x) = 0

Rewrite using trig identities

- cos (2 x) = 0

Divide both sides by

- 1

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

cos (θ) = 1 + 2 cos (θ)

cos (β) = \frac{2}{7}

tan (x) = \frac{930}{1793}

sin (x) + cos (x) = 0.2

sin (x) cos (x) = - \frac{2}{4}

What is the general solution for solvefor x,sin^2(x)=cos^2(x) ?
The general solution for solvefor x,sin^2(x)=cos^2(x) is x= pi/4+pin,x=(3pi)/4+pin