What is the general solution for 5tan^2(t)-tan(t)=0 ?

The general solution for 5tan^2(t)-tan(t)=0 is t=0.19739…+pin,t=pin

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5tan^2(t)-tan(t)=0

5 tan^{2} (t) - tan (t) = 0

t = 0.19739 \dots + πn, t = πn

Solution steps

5 tan^{2} (t) - tan (t) = 0

Solve by substitution

tan (t) = \frac{1}{5}, tan (t) = 0

tan (t) = \frac{1}{5} : t = arctan (\frac{1}{5}) + πn

tan (t) = 0 : t = πn

Combine all the solutions

t = arctan (\frac{1}{5}) + πn, t = πn

Show solutions in decimal form

t = 0.19739 \dots + πn, t = πn

sin (x) = \frac{9}{16}

24 = 32 + 8 - 2 \cdot 32 \cdot 8 \cdot cos (θ)

sin (4 5^{\circ} + a) cos (4 5^{\circ} + a) = \frac{2}{2}

tan (x) \cdot sin (x) = 5219

sin (z) = 2

What is the general solution for 5tan^2(t)-tan(t)=0 ?
The general solution for 5tan^2(t)-tan(t)=0 is t=0.19739…+pin,t=pin