What is the general solution for cos(x)=-1/2 ,0<x<2pi ?

The general solution for cos(x)=-1/2 ,0<x<2pi is x=(2pi)/3 ,x=(4pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(x)=-1/2 ,0<x<2pi

cos (x) = - \frac{1}{2}, 0 < x < 2 π

x = \frac{2 π}{3}, x = \frac{4 π}{3}

Solution steps

cos (x) = - \frac{1}{2}, 0 < x < 2 π

General solutions for

cos (x) = - \frac{1}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solutions for the range

0 < x < 2 π

x = \frac{2 π}{3}, x = \frac{4 π}{3}

cot (θ) = cos (θ)

3 sin^{2} (θ) - cos (θ) + 1 = 0

2 - 2 cos^{2} (x) = 0

3 csc^{3} (x) - 4 csc (x) = 0

tan (θ) = \frac{6.06}{- 33.5}

What is the general solution for cos(x)=-1/2 ,0<x<2pi ?
The general solution for cos(x)=-1/2 ,0<x<2pi is x=(2pi)/3 ,x=(4pi)/3