What is the general solution for 3sin^2(θ)-cos(θ)+1=0 ?

The general solution for 3sin^2(θ)-cos(θ)+1=0 is θ=2pin

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3sin^2(θ)-cos(θ)+1=0

3 sin^{2} (θ) - cos (θ) + 1 = 0

θ = 2 πn

Solution steps

3 sin^{2} (θ) - cos (θ) + 1 = 0

Rewrite using trig identities

4 - cos (θ) - 3 cos^{2} (θ) = 0

Solve by substitution

cos (θ) = - \frac{4}{3}, cos (θ) = 1

cos (θ) = - \frac{4}{3} :

No Solution

cos (θ) = 1 : θ = 2 πn

Combine all the solutions

θ = 2 πn

2 - 2 cos^{2} (x) = 0

3 csc^{3} (x) - 4 csc (x) = 0

tan (θ) = \frac{6.06}{- 33.5}

csc (θ) = \frac{13}{2}, sec (θ) = \frac{13}{3}

4 cos^{2} (x) + cos (2 x) - 7 cos (x) = - 2, 0^{\circ} \leq x \leq 36 0^{\circ}

What is the general solution for 3sin^2(θ)-cos(θ)+1=0 ?
The general solution for 3sin^2(θ)-cos(θ)+1=0 is θ=2pin