What is the general solution for sin(3x-pi/2)=-(sqrt(3))/2 ,(3pi,4pi) ?

The general solution for sin(3x-pi/2)=-(sqrt(3))/2 ,(3pi,4pi) is x=(59pi)/(18),x=(61pi)/(18)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(3x-pi/2)=-(sqrt(3))/2 ,(3pi,4pi)

sin (3 x - \frac{π}{2}) = - \frac{3}{2}, (3 π, 4 π)

x = \frac{59 π}{18}, x = \frac{61 π}{18}

Solution steps

sin (3 x - \frac{π}{2}) = - \frac{3}{2}, (3 π, 4 π)

General solutions for

sin (3 x - \frac{π}{2}) = - \frac{3}{2}

3 x - \frac{π}{2} = \frac{4 π}{3} + 2 πn, 3 x - \frac{π}{2} = \frac{5 π}{3} + 2 πn

Solve

3 x - \frac{π}{2} = \frac{4 π}{3} + 2 πn : x = \frac{2 πn}{3} + \frac{11 π}{18}

Solve

3 x - \frac{π}{2} = \frac{5 π}{3} + 2 πn : x = \frac{2 πn}{3} + \frac{13 π}{18}

x = \frac{2 πn}{3} + \frac{11 π}{18}, x = \frac{2 πn}{3} + \frac{13 π}{18}

Solutions for the range

(3 π, 4 π)

x = \frac{59 π}{18}, x = \frac{61 π}{18}

2 sin^{2} (x) - 7 cos (x) - 5 = 0

cos (x) = sin (0)

1 = \frac{1}{0.5} sin (x + 3 0^{\circ})

- tan^{2} (θ) = - 1 + sec (θ)

x, y = sin (x^{c o s (y)})

What is the general solution for sin(3x-pi/2)=-(sqrt(3))/2 ,(3pi,4pi) ?
The general solution for sin(3x-pi/2)=-(sqrt(3))/2 ,(3pi,4pi) is x=(59pi)/(18),x=(61pi)/(18)