What is the general solution for 3sin^2(θ)-3=0 ?

The general solution for 3sin^2(θ)-3=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3sin^2(θ)-3=0

3 sin^{2} (θ) - 3 = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

3 sin^{2} (θ) - 3 = 0

Solve by substitution

sin (θ) = 1, sin (θ) = - 1

sin (θ) = 1 : θ = \frac{π}{2} + 2 πn

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

sin (x) cos (x) = sin^{2} (x)

sin (x) = \frac{17}{8}

3 csc (θ) = 2

4 sin (x) + 8 = 8

2 cos^{2} (t) - 8 sin^{2} (t) cos (t) - 1 = 0

What is the general solution for 3sin^2(θ)-3=0 ?
The general solution for 3sin^2(θ)-3=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin