What is the general solution for sin((3pi)/2-0)=-cos(x) ?

The general solution for sin((3pi)/2-0)=-cos(x) is x=2pin

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sin((3pi)/2-0)=-cos(x)

sin (\frac{3 π}{2} - 0) = - cos (x)

x = 2 πn

Solution steps

sin (\frac{3 π}{2} - 0) = - cos (x)

sin (\frac{3 π}{2} - 0) = - 1

- 1 = - cos (x)

Move

cos (x)

to the left side

- 1 + cos (x) = 0

Move

1

to the right side

cos (x) = 1

General solutions for

cos (x) = 1

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn

sec (x) = - \frac{7}{4}

28 cos^{2} (θ) = 7

3 - cos (6 x) \cdot 6 = 0

sin (x) - cos (x) = 1, 0 \leq x \leq 36 0^{\circ}

cos (x) = 0, 6

What is the general solution for sin((3pi)/2-0)=-cos(x) ?
The general solution for sin((3pi)/2-0)=-cos(x) is x=2pin