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Popular >

(2cos(2θ))=2

Solution

(2 cos (2 θ)) = 2

Solution

θ = πn

+1

Solution steps

(2 cos (2 θ)) = 2

Divide both sides by

2

cos (2 θ) = 1

General solutions for

cos (2 θ) = 1

2 θ = 0 + 2 πn

Solve

2 θ = 0 + 2 πn : θ = πn

θ = πn

Popular Examples

5sin^2(x)=9tan(x)

5 sin^{2} (x) = 9 tan (x)

cos (θ) = \frac{5}{4}

cos(x)=sin(2x),0<= x<= 2pi

cos (x) = sin (2 x), 0 \leq x \leq 2 π

tan(θ)(sin(θ)-1)=0

tan (θ) (sin (θ) - 1) = 0

sin (θ) - 4 = - 5

Frequently Asked Questions (FAQ)

What is the general solution for (2cos(2θ))=2 ?
The general solution for (2cos(2θ))=2 is θ=pin