What is the general solution for tan(θ)(sin(θ)-1)=0 ?

The general solution for tan(θ)(sin(θ)-1)=0 is θ=pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(θ)(sin(θ)-1)=0

tan (θ) (sin (θ) - 1) = 0

θ = πn

Solution steps

tan (θ) (sin (θ) - 1) = 0

Solving each part separately

tan (θ) = 0 or sin (θ) - 1 = 0

tan (θ) = 0 : θ = πn

sin (θ) - 1 = 0 : θ = \frac{π}{2} + 2 πn

Combine all the solutions

θ = πn, θ = \frac{π}{2} + 2 πn

Since the equation is undefined for:

\frac{π}{2} + 2 πn

θ = πn

sin (θ) - 4 = - 5

sin (θ) - 4 = - 3

csc^{2} (x) = 4 cot^{2} (x)

cot^{2} (3 x) - tan^{2} (3 x) = 0

x, cos (x) = 10

What is the general solution for tan(θ)(sin(θ)-1)=0 ?
The general solution for tan(θ)(sin(θ)-1)=0 is θ=pin