What is the general solution for sec((2pi)/3+x)=2 ?

The general solution for sec((2pi)/3+x)=2 is x=2pin-pi/3 ,x=2pin+pi

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sec((2pi)/3+x)=2

sec (\frac{2 π}{3} + x) = 2

x = 2 πn - \frac{π}{3}, x = 2 πn + π

Solution steps

sec (\frac{2 π}{3} + x) = 2

General solutions for

sec (\frac{2 π}{3} + x) = 2

\frac{2 π}{3} + x = \frac{π}{3} + 2 πn, \frac{2 π}{3} + x = \frac{5 π}{3} + 2 πn

Solve

\frac{2 π}{3} + x = \frac{π}{3} + 2 πn : x = 2 πn - \frac{π}{3}

Solve

\frac{2 π}{3} + x = \frac{5 π}{3} + 2 πn : x = 2 πn + π

x = 2 πn - \frac{π}{3}, x = 2 πn + π

sin (t) = \frac{7}{9}, sin (2 t)

\frac{8}{17} = sin (2 x)

sec (2 x) + tan (2 x) = 2

sec (2 x) + tan (2 x) = 9

2 + 3 cos^{2} (x) = sin^{2} (x) + 4 cos (x)

What is the general solution for sec((2pi)/3+x)=2 ?
The general solution for sec((2pi)/3+x)=2 is x=2pin-pi/3 ,x=2pin+pi