What is the general solution for cos(x)= 1/4 ,0<= x<= 2pi ?

The general solution for cos(x)= 1/4 ,0<= x<= 2pi is x=1.31811…,x=2pi-1.31811…

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cos(x)= 1/4 ,0<= x<= 2pi

cos (x) = \frac{1}{4}, 0 \leq x \leq 2 π

x = 1.31811 \dots, x = 2 π - 1.31811 \dots

Solution steps

cos (x) = \frac{1}{4}, 0 \leq x \leq 2 π

Apply trig inverse properties

x = arccos (\frac{1}{4}) + 2 πn, x = 2 π - arccos (\frac{1}{4}) + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = arccos (\frac{1}{4}), x = 2 π - arccos (\frac{1}{4})

Show solutions in decimal form

x = 1.31811 \dots, x = 2 π - 1.31811 \dots

tan^{2} (x) + 1 = a^{2}

2 = 2 cos (t)

50 sin (4 5^{\circ}) = 600 sin (θ)

a, tan (a \cdot x^{0.5}) = - x^{0.5}

sin (x) = 35, csc (x)

What is the general solution for cos(x)= 1/4 ,0<= x<= 2pi ?
The general solution for cos(x)= 1/4 ,0<= x<= 2pi is x=1.31811…,x=2pi-1.31811…