What is the general solution for cos(2x+30)= 1/2 ,0<= x<= 360 ?

The general solution for cos(2x+30)= 1/2 ,0<= x<= 360 is x=(-90+5220)/6

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cos(2x+30)= 1/2 ,0<= x<= 360

cos (2 x + 30) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

x = \frac{- 90 + 522 0 ^{\circ}}{6}

Solution steps

cos (2 x + 30) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

General solutions for

cos (2 x + 30) = \frac{1}{2}

2 x + 30 = 6 0^{\circ} + 36 0^{\circ} n, 2 x + 30 = 30 0^{\circ} + 36 0^{\circ} n

Solve

2 x + 30 = 6 0^{\circ} + 36 0^{\circ} n : x = - 15 + 18 0^{\circ} n + 3 0^{\circ}

Solve

2 x + 30 = 30 0^{\circ} + 36 0^{\circ} n : x = - 15 + 18 0^{\circ} n + 15 0^{\circ}

x = - 15 + 18 0^{\circ} n + 3 0^{\circ}, x = - 15 + 18 0^{\circ} n + 15 0^{\circ}

Solutions for the range

0 \leq x \leq 36 0^{\circ}

x = \frac{- 90 + 522 0 ^{\circ}}{6}

tan (θ) = \frac{43}{90}

2 sin (2 x + \frac{π}{3}) = 1

sec (x) = 2, cos (x)

- cosh (sech (x)) (sech (x) tanh (x)) = 0

\frac{sin ( 9 7 ^{\circ} )}{14} = \frac{sin ( b )}{10}

What is the general solution for cos(2x+30)= 1/2 ,0<= x<= 360 ?
The general solution for cos(2x+30)= 1/2 ,0<= x<= 360 is x=(-90+5220)/6