What is the general solution for 2cos(2θ)+3=2 ?

The general solution for 2cos(2θ)+3=2 is θ= pi/3+pin,θ=(2pi)/3+pin

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2cos(2θ)+3=2

2 cos (2 θ) + 3 = 2

θ = \frac{π}{3} + πn, θ = \frac{2 π}{3} + πn

Solution steps

2 cos (2 θ) + 3 = 2

Move

3

to the right side

2 cos (2 θ) = - 1

Divide both sides by

2

cos (2 θ) = - \frac{1}{2}

General solutions for

cos (2 θ) = - \frac{1}{2}

2 θ = \frac{2 π}{3} + 2 πn, 2 θ = \frac{4 π}{3} + 2 πn

Solve

2 θ = \frac{2 π}{3} + 2 πn : θ = \frac{π}{3} + πn

Solve

2 θ = \frac{4 π}{3} + 2 πn : θ = \frac{2 π}{3} + πn

θ = \frac{π}{3} + πn, θ = \frac{2 π}{3} + πn

sin (\frac{3 π}{2} - 2 x) = sin (x)

α, sin (α) - sin (β) = cos (β) - cos (α)

- \frac{6}{7} = tan (t)

sin (2 x) = 3

sin (3 x) cos (2 x) = 0

What is the general solution for 2cos(2θ)+3=2 ?
The general solution for 2cos(2θ)+3=2 is θ= pi/3+pin,θ=(2pi)/3+pin