What is the general solution for sin(3x)cos(2x)=0 ?

The general solution for sin(3x)cos(2x)=0 is x=(2pin)/3 ,x= pi/3+(2pin)/3 ,x= pi/4+pin,x=(3pi)/4+pin

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sin(3x)cos(2x)=0

sin (3 x) cos (2 x) = 0

x = \frac{2 πn}{3}, x = \frac{π}{3} + \frac{2 πn}{3}, x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

sin (3 x) cos (2 x) = 0

Solving each part separately

sin (3 x) = 0 or cos (2 x) = 0

sin (3 x) = 0 : x = \frac{2 πn}{3}, x = \frac{π}{3} + \frac{2 πn}{3}

cos (2 x) = 0 : x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{2 πn}{3}, x = \frac{π}{3} + \frac{2 πn}{3}, x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

sin (- 2 x) = \frac{- 1}{2}

2 cos (x) sin (x) = 1

cos (2 x + 15) = 0.3

\frac{sin ^{2} ( x )}{cos ( x )} = 16.33

- 2 sin (θ) + 2 sin^{2} (θ) = 0

What is the general solution for sin(3x)cos(2x)=0 ?
The general solution for sin(3x)cos(2x)=0 is x=(2pin)/3 ,x= pi/3+(2pin)/3 ,x= pi/4+pin,x=(3pi)/4+pin