What is the general solution for cos(2x+15)=0.3 ?

The general solution for cos(2x+15)=0.3 is x=pin-15/2+(1.26610…)/2 ,x=pi+pin-15/2-(1.26610…)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(2x+15)=0.3

cos (2 x + 15) = 0.3

x = πn - \frac{15}{2} + \frac{1.26610 \dots}{2}, x = π + πn - \frac{15}{2} - \frac{1.26610 \dots}{2}

Solution steps

cos (2 x + 15) = 0.3

Apply trig inverse properties

2 x + 15 = arccos (0.3) + 2 πn, 2 x + 15 = 2 π - arccos (0.3) + 2 πn

Solve

2 x + 15 = arccos (0.3) + 2 πn : x = πn - \frac{15}{2} + \frac{arccos ( 0.3 )}{2}

Solve

2 x + 15 = 2 π - arccos (0.3) + 2 πn : x = π + πn - \frac{15}{2} - \frac{arccos ( 0.3 )}{2}

x = πn - \frac{15}{2} + \frac{arccos ( 0.3 )}{2}, x = π + πn - \frac{15}{2} - \frac{arccos ( 0.3 )}{2}

Show solutions in decimal form

x = πn - \frac{15}{2} + \frac{1.26610 \dots}{2}, x = π + πn - \frac{15}{2} - \frac{1.26610 \dots}{2}

\frac{sin ^{2} ( x )}{cos ( x )} = 16.33

- 2 sin (θ) + 2 sin^{2} (θ) = 0

sin (2 π x) cos (π x) + cos (2 π x) sin (π x) = - 1

0 = - (sin (6.9256 - x) + (sin (- x)))

- 4 π^{2} sin (2 π x) = 0

What is the general solution for cos(2x+15)=0.3 ?
The general solution for cos(2x+15)=0.3 is x=pin-15/2+(1.26610…)/2 ,x=pi+pin-15/2-(1.26610…)/2