What is the general solution for 0=-(sin(6.9256-x)+(sin(-x))) ?

The general solution for 0=-(sin(6.9256-x)+(sin(-x))) is x=-2pin+(6.9256)/2 ,x=-pi+(6.9256)/2-2pin

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0=-(sin(6.9256-x)+(sin(-x)))

0 = - (sin (6.9256 - x) + (sin (- x)))

x = - 2 πn + \frac{6.9256}{2}, x = - π + \frac{6.9256}{2} - 2 πn

Solution steps

0 = - (sin (6.9256 - x) + (sin (- x)))

Switch sides

- (sin (6.9256 - x) + sin (- x)) = 0

Rewrite using trig identities

1.89770 \dots sin (\frac{6.9256 - 2 x}{2}) = 0

Divide both sides by

1.89770 \dots

sin (\frac{6.9256 - 2 x}{2}) = 0

General solutions for

sin (\frac{6.9256 - 2 x}{2}) = 0

\frac{6.9256 - 2 x}{2} = 0 + 2 πn, \frac{6.9256 - 2 x}{2} = π + 2 πn

Solve

\frac{6.9256 - 2 x}{2} = 0 + 2 πn : x = - 2 πn + \frac{6.9256}{2}

Solve

\frac{6.9256 - 2 x}{2} = π + 2 πn : x = - π + \frac{6.9256}{2} - 2 πn

x = - 2 πn + \frac{6.9256}{2}, x = - π + \frac{6.9256}{2} - 2 πn

- 4 π^{2} sin (2 π x) = 0

- 9 sin (y) = 0

6 + 4 cos (2 x) = 2 - 4 cos (x)

x, cos (x) = y

tan (θ) = \frac{48}{90}

What is the general solution for 0=-(sin(6.9256-x)+(sin(-x))) ?
The general solution for 0=-(sin(6.9256-x)+(sin(-x))) is x=-2pin+(6.9256)/2 ,x=-pi+(6.9256)/2-2pin