What is the general solution for 10tan(θ)+9=0 ?

The general solution for 10tan(θ)+9=0 is θ=-0.73281…+pin

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10tan(θ)+9=0

10 tan (θ) + 9 = 0

θ = - 0.73281 \dots + πn

Degrees

θ = - 41.98721 \dots^{\circ} + 18 0^{\circ} n

Solution steps

10 tan (θ) + 9 = 0

Move

9

to the right side

10 tan (θ) + 9 = 0

Subtract

9

from both sides

10 tan (θ) + 9 - 9 = 0 - 9

Simplify

10 tan (θ) = - 9

10 tan (θ) = - 9

Divide both sides by

10

10 tan (θ) = - 9

Divide both sides by

10

\frac{10 tan ( θ )}{10} = \frac{- 9}{10}

Simplify

tan (θ) = - \frac{9}{10}

tan (θ) = - \frac{9}{10}

Apply trig inverse properties

tan (θ) = - \frac{9}{10}

General solutions for

tan (θ) = - \frac{9}{10}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

θ = arctan (- \frac{9}{10}) + πn

θ = arctan (- \frac{9}{10}) + πn

Show solutions in decimal form

θ = - 0.73281 \dots + πn

189.4 = 100 tan^{2} (4 5^{\circ} - \frac{x}{2})

5 = sin (x)

\frac{20}{3} sin (10 x) + 5 cos (10 x) = 0

5 sin^{2} (x) = 0

(\frac{( 1 - sin ^{2} ( x ) )}{( 1 + 2 \cdot sin ^{2} ( x ) )}) = 0.4

What is the general solution for 10tan(θ)+9=0 ?
The general solution for 10tan(θ)+9=0 is θ=-0.73281…+pin