What is the general solution for 5sin^2(x)=0 ?

The general solution for 5sin^2(x)=0 is x=2pin,x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5sin^2(x)=0

5 sin^{2} (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

5 sin^{2} (x) = 0

Divide both sides by

5

sin (x) = 0

General solutions for

sin (x) = 0

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn, x = π + 2 πn

(\frac{( 1 - sin ^{2} ( x ) )}{( 1 + 2 \cdot sin ^{2} ( x ) )}) = 0.4

cos (3 x + \frac{π}{4}) = - \frac{3}{2}

1 = cos (\frac{π}{64} \cdot t^{2})

sin (x) - \frac{1}{4} = 0

2 csc (θ) - 2 = 0

What is the general solution for 5sin^2(x)=0 ?
The general solution for 5sin^2(x)=0 is x=2pin,x=pi+2pin