What is the general solution for 1=cos(pi/(64)*t^2) ?

The general solution for 1=cos(pi/(64)*t^2) is t=8sqrt(2)sqrt(n),t=-8sqrt(2)sqrt(n)

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1=cos(pi/(64)*t^2)

1 = cos (\frac{π}{64} \cdot t^{2})

t = 82 n, t = - 82 n

Solution steps

1 = cos (\frac{π}{64} t^{2})

Switch sides

cos (\frac{π}{64} t^{2}) = 1

General solutions for

cos (\frac{π}{64} t^{2}) = 1

\frac{π}{64} t^{2} = 0 + 2 πn

Solve

\frac{π}{64} t^{2} = 0 + 2 πn : t = 82 n, t = - 82 n

t = 82 n, t = - 82 n

sin (x) - \frac{1}{4} = 0

2 csc (θ) - 2 = 0

sin (θ) = \frac{5}{4}

100 = 5040 cos (θ)

cos (3 x) = \frac{2}{3}

What is the general solution for 1=cos(pi/(64)*t^2) ?
The general solution for 1=cos(pi/(64)*t^2) is t=8sqrt(2)sqrt(n),t=-8sqrt(2)sqrt(n)