What is the general solution for 2sin(5x)-1=0 ?

The general solution for 2sin(5x)-1=0 is x= pi/(30)+(2pin)/5 ,x= pi/6+(2pin)/5

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2sin(5x)-1=0

2 sin (5 x) - 1 = 0

x = \frac{π}{30} + \frac{2 πn}{5}, x = \frac{π}{6} + \frac{2 πn}{5}

Solution steps

2 sin (5 x) - 1 = 0

Move

1

to the right side

2 sin (5 x) = 1

Divide both sides by

2

sin (5 x) = \frac{1}{2}

General solutions for

sin (5 x) = \frac{1}{2}

5 x = \frac{π}{6} + 2 πn, 5 x = \frac{5 π}{6} + 2 πn

Solve

5 x = \frac{π}{6} + 2 πn : x = \frac{π}{30} + \frac{2 πn}{5}

Solve

5 x = \frac{5 π}{6} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}, x = \frac{π}{6} + \frac{2 πn}{5}

cos (x) = \frac{2.3}{2.8}

3000 = 5000 [cos (\frac{π}{45} (t - 6))]

2 + cos (θ) = 5 cos (θ)

11 = 12 + 3.1 cos (\frac{2 π}{365} t)

θ, 6 sin^{2} (θ) - 3 = 0

What is the general solution for 2sin(5x)-1=0 ?
The general solution for 2sin(5x)-1=0 is x= pi/(30)+(2pin)/5 ,x= pi/6+(2pin)/5