What is the general solution for 2sec^2(x)-5sec(x)+2=0,0<= x<= 360 ?

The general solution for 2sec^2(x)-5sec(x)+2=0,0<= x<= 360 is x=60,x=300

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sec^2(x)-5sec(x)+2=0,0<= x<= 360

2 sec^{2} (x) - 5 sec (x) + 2 = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

x = 6 0^{\circ}, x = 30 0^{\circ}

Solution steps

2 sec^{2} (x) - 5 sec (x) + 2 = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

Solve by substitution

sec (x) = 2, sec (x) = \frac{1}{2}

sec (x) = 2, 0 \leq x \leq 36 0^{\circ} : x = 6 0^{\circ}, x = 30 0^{\circ}

sec (x) = \frac{1}{2}, 0 \leq x \leq 36 0^{\circ} :

No Solution

Combine all the solutions

x = 6 0^{\circ}, x = 30 0^{\circ}

2 sin (5 x) + 3 = 0, 0 \leq x \leq 2 π

sin (2 θ) = - \frac{24}{25}

sin (4 x) + cos (4 x) = 1

- 4 cos (x) = - sin^{2} (x) + 4, 0 \leq x \leq 2 π

0 = cos^{2} (\frac{π}{12} t)

What is the general solution for 2sec^2(x)-5sec(x)+2=0,0<= x<= 360 ?
The general solution for 2sec^2(x)-5sec(x)+2=0,0<= x<= 360 is x=60,x=300