What is the general solution for 0=cos^2(pi/(12)t) ?

The general solution for 0=cos^2(pi/(12)t) is t=6+24n,t=18+24n

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0=cos^2(pi/(12)t)

0 = cos^{2} (\frac{π}{12} t)

t = 6 + 24 n, t = 18 + 24 n

Solution steps

0 = cos^{2} (\frac{π}{12} t)

Switch sides

cos^{2} (\frac{π}{12} t) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

cos (\frac{π}{12} t) = 0

General solutions for

cos (\frac{π}{12} t) = 0

\frac{π}{12} t = \frac{π}{2} + 2 πn, \frac{π}{12} t = \frac{3 π}{2} + 2 πn

Solve

\frac{π}{12} t = \frac{π}{2} + 2 πn : t = 6 + 24 n

Solve

\frac{π}{12} t = \frac{3 π}{2} + 2 πn : t = 18 + 24 n

t = 6 + 24 n, t = 18 + 24 n

sec^{2} (x) + 2 sec (x) + 4 = 0

cos (A) = 0.7865

sin (x) = cos (2 x + 5 1^{\circ})

sin (x) = \frac{π}{4}

cos (x) = 45.7

What is the general solution for 0=cos^2(pi/(12)t) ?
The general solution for 0=cos^2(pi/(12)t) is t=6+24n,t=18+24n