What is the general solution for sqrt(2)cos(θ)+1=0 ?

The general solution for sqrt(2)cos(θ)+1=0 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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sqrt(2)cos(θ)+1=0

2 cos (θ) + 1 = 0

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

2 cos (θ) + 1 = 0

Move

1

to the right side

2 cos (θ) = - 1

Divide both sides by

2

cos (θ) = - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

\frac{1}{1 - sin ( x )} = 2 sec^{2} (x) + tan (x) sec (x)

42 tan (x) - 2 = 32 tan (x)

7 sin (2 x) + 12 cos (x) = 0

θ, cos (θ) = - cos (4 0^{\circ})

- 1 - 2 sec^{2} (x) = - 3 sec^{2} (x)

What is the general solution for sqrt(2)cos(θ)+1=0 ?
The general solution for sqrt(2)cos(θ)+1=0 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin