What is the general solution for solvefor θ,cos(θ)=-cos(40) ?

The general solution for solvefor θ,cos(θ)=-cos(40) is θ=2.44346…+360n,θ=-2.44346…+360n

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solvefor θ,cos(θ)=-cos(40)

solve for

θ, cos (θ) = - cos (4 0^{\circ})

θ = 2.44346 \dots + 36 0^{\circ} n, θ = - 2.44346 \dots + 36 0^{\circ} n

Solution steps

cos (θ) = - cos (4 0^{\circ})

Apply trig inverse properties

θ = arccos (- cos (4 0^{\circ})) + 36 0^{\circ} n, θ = - arccos (- cos (4 0^{\circ})) + 36 0^{\circ} n

Show solutions in decimal form

θ = 2.44346 \dots + 36 0^{\circ} n, θ = - 2.44346 \dots + 36 0^{\circ} n

- 1 - 2 sec^{2} (x) = - 3 sec^{2} (x)

tanh (x + 1) + 1 = 2

sin (2 θ) = 0.9076

7 sin (B) + 3 = sin (B) + 2

4 cos (x) = 3

What is the general solution for solvefor θ,cos(θ)=-cos(40) ?
The general solution for solvefor θ,cos(θ)=-cos(40) is θ=2.44346…+360n,θ=-2.44346…+360n