What is the general solution for 2cos(x)+sqrt(3)=0,0<= x<= 2pi ?

The general solution for 2cos(x)+sqrt(3)=0,0<= x<= 2pi is x=(5pi)/6 ,x=(7pi)/6

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2cos(x)+sqrt(3)=0,0<= x<= 2pi

2 cos (x) + 3 = 0, 0 \leq x \leq 2 π

x = \frac{5 π}{6}, x = \frac{7 π}{6}

Solution steps

2 cos (x) + 3 = 0, 0 \leq x \leq 2 π

Move

3

to the right side

2 cos (x) = - 3

Divide both sides by

2

cos (x) = - \frac{3}{2}

General solutions for

cos (x) = - \frac{3}{2}

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{5 π}{6}, x = \frac{7 π}{6}

\frac{cot ^{2} ( x )}{1 + sin ( x )} = \frac{csc ( x ) - 1}{sin ^{2} ( x )}

tan (x) = 2.3

2 sec^{2} (x) = 5 tan (x) + 5

tan^{2} (x) - 2 tan (x) = 3

x, y = arcsin (x y)

What is the general solution for 2cos(x)+sqrt(3)=0,0<= x<= 2pi ?
The general solution for 2cos(x)+sqrt(3)=0,0<= x<= 2pi is x=(5pi)/6 ,x=(7pi)/6