What is the general solution for ((-sqrt(2))/2)(sin(θ)-cos(θ))=0 ?

The general solution for ((-sqrt(2))/2)(sin(θ)-cos(θ))=0 is θ= pi/4+pin

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((-sqrt(2))/2)(sin(θ)-cos(θ))=0

(\frac{- 2}{2}) (sin (θ) - cos (θ)) = 0

θ = \frac{π}{4} + πn

Solution steps

(\frac{- 2}{2}) (sin (θ) - cos (θ)) = 0

Rewrite using trig identities

\frac{- tan ( θ ) + 1}{2} = 0

Multiply both sides by

2

- tan (θ) + 1 = 0

Move

1

to the right side

- tan (θ) = - 1

Divide both sides by

- 1

tan (θ) = 1

General solutions for

tan (θ) = 1

θ = \frac{π}{4} + πn

3 \cdot sin (x) + 4 \cdot cos (x) = 2

1 = sin (x) + cos (x)

cos (2 t) - cos (t) = - 0.5, 0 < t < 2 π

2 sin (x) - sin (x) cos (x) = 0

3 sin (x) - 2 cos (x) = 7

What is the general solution for ((-sqrt(2))/2)(sin(θ)-cos(θ))=0 ?
The general solution for ((-sqrt(2))/2)(sin(θ)-cos(θ))=0 is θ= pi/4+pin