What is the general solution for 2*sin(3θ)=2 ?

The general solution for 2*sin(3θ)=2 is θ= pi/6+(2pin)/3

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2*sin(3θ)=2

2 \cdot sin (3 θ) = 2

θ = \frac{π}{6} + \frac{2 πn}{3}

Solution steps

2 sin (3 θ) = 2

Divide both sides by

2

sin (3 θ) = 1

General solutions for

sin (3 θ) = 1

3 θ = \frac{π}{2} + 2 πn

Solve

3 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{6} + \frac{2 πn}{3}

θ = \frac{π}{6} + \frac{2 πn}{3}

cos (x) = \frac{9.8}{( 0.1 ) ( 6.28 ) ^{2}}

cos^{4} (x) - 3 cos^{2} (x) - 4 = 0

- 4 sin (t) + 5 cos (t) = 0

- sin (θ) + 5 cos (2 θ) = 0

θ, r = 2 sin (θ)

What is the general solution for 2*sin(3θ)=2 ?
The general solution for 2*sin(3θ)=2 is θ= pi/6+(2pin)/3