What is the general solution for sin(θ)=-0 ?

The general solution for sin(θ)=-0 is θ=2pin,θ=pi+2pin

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sin(θ)=-0

sin (θ) = - 0

θ = 2 πn, θ = π + 2 πn

Solution steps

sin (θ) = - 0

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

tan (x) = \frac{15}{12}

6 sin (θ) + 3 sin (θ) tan (θ) = 3 sin (θ)

cos (2 x) sin (x) = 1

sin (θ) = 10

17. 6^{2} = 1 5^{2} + 13. 1^{2} - 2 (15) (13.1) \cdot cos (A)

What is the general solution for sin(θ)=-0 ?
The general solution for sin(θ)=-0 is θ=2pin,θ=pi+2pin