What is the general solution for sin(3x)-2=-3sin(3x) ?

The general solution for sin(3x)-2=-3sin(3x) is x= pi/(18)+(2pin)/3 ,x=(5pi}{18}+\frac{2pin)/3

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sin(3x)-2=-3sin(3x)

sin (3 x) - 2 = - 3 sin (3 x)

x = \frac{π}{18} + \frac{2 πn}{3}, x = \frac{5 π}{18} + \frac{2 πn}{3}

Solution steps

sin (3 x) - 2 = - 3 sin (3 x)

Solve by substitution

sin (3 x) = \frac{1}{2}

sin (3 x) = \frac{1}{2} : x = \frac{π}{18} + \frac{2 πn}{3}, x = \frac{5 π}{18} + \frac{2 πn}{3}

Combine all the solutions

x = \frac{π}{18} + \frac{2 πn}{3}, x = \frac{5 π}{18} + \frac{2 πn}{3}

sin (a) = \frac{1}{5}

θ, cos (θ) = \frac{2}{3}

x, arcsin (x) = arccos (y)

sin (x) = \frac{4.9}{7.5}

\frac{1}{cos ( x )} + sec^{2} (x) - 1 - cos (x) = 0

What is the general solution for sin(3x)-2=-3sin(3x) ?
The general solution for sin(3x)-2=-3sin(3x) is x= pi/(18)+(2pin)/3 ,x=(5pi}{18}+\frac{2pin)/3