What is the general solution for cos(x)+cos^2(x)=1 ?

The general solution for cos(x)+cos^2(x)=1 is x=0.90455…+2pin,x=2pi-0.90455…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(x)+cos^2(x)=1

cos (x) + cos^{2} (x) = 1

x = 0.90455 \dots + 2 πn, x = 2 π - 0.90455 \dots + 2 πn

Solution steps

cos (x) + cos^{2} (x) = 1

Solve by substitution

cos (x) = \frac{- 1 + 5}{2}, cos (x) = \frac{- 1 - 5}{2}

cos (x) = \frac{- 1 + 5}{2} : x = arccos (\frac{- 1 + 5}{2}) + 2 πn, x = 2 π - arccos (\frac{- 1 + 5}{2}) + 2 πn

cos (x) = \frac{- 1 - 5}{2} :

No Solution

Combine all the solutions

x = arccos (\frac{- 1 + 5}{2}) + 2 πn, x = 2 π - arccos (\frac{- 1 + 5}{2}) + 2 πn

Show solutions in decimal form

x = 0.90455 \dots + 2 πn, x = 2 π - 0.90455 \dots + 2 πn

6 tan (x) - 5 csc (x) = 0

2 (19) tan (\frac{θ}{2}) = 6.3

3 csc (x) - 6 = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

tan (\frac{x}{2} + \frac{π}{3}) = - 1

- sec^{2} (x) + 1 = - 5 sec (x) - 5

What is the general solution for cos(x)+cos^2(x)=1 ?
The general solution for cos(x)+cos^2(x)=1 is x=0.90455…+2pin,x=2pi-0.90455…+2pin