What is the general solution for sin((2pi(t+101.75))/(365))=-1 ?

The general solution for sin((2pi(t+101.75))/(365))=-1 is t=364.99999…n+172

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sin((2pi(t+101.75))/(365))=-1

sin (\frac{2 π ( t + 101.75 )}{365}) = - 1

t = 364.99999 \dots n + 172

Solution steps

sin (\frac{2 π ( t + 101.75 )}{365}) = - 1

General solutions for

sin (\frac{2 π ( t + 101.75 )}{365}) = - 1

\frac{2 π ( t + 101.75 )}{365} = \frac{3 π}{2} + 2 πn

Solve

\frac{2 π ( t + 101.75 )}{365} = \frac{3 π}{2} + 2 πn : t = 364.99999 \dots n + 172

t = 364.99999 \dots n + 172

2 sin^{2} (θ) - 2 = cos^{2} (θ), 0 \leq θ \leq 2 π

cos (θ) = - \frac{7}{5}

sin (π + x) = sin (x)

cos (x) = - \frac{2}{π}

23 cos (z) + 2 sin (z) = 0

What is the general solution for sin((2pi(t+101.75))/(365))=-1 ?
The general solution for sin((2pi(t+101.75))/(365))=-1 is t=364.99999…n+172