What is the general solution for sin(t+pi/4)= 1/2 ,pi<= t<= (7pi)/2 ?

The general solution for sin(t+pi/4)= 1/2 ,pi<= t<= (7pi)/2 is t=(23pi)/(12),t=(31pi)/(12)

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sin(t+pi/4)= 1/2 ,pi<= t<= (7pi)/2

sin (t + \frac{π}{4}) = \frac{1}{2}, π \leq t \leq \frac{7 π}{2}

t = \frac{23 π}{12}, t = \frac{31 π}{12}

Solution steps

sin (t + \frac{π}{4}) = \frac{1}{2}, π \leq t \leq \frac{7 π}{2}

General solutions for

sin (t + \frac{π}{4}) = \frac{1}{2}

t + \frac{π}{4} = \frac{π}{6} + 2 πn, t + \frac{π}{4} = \frac{5 π}{6} + 2 πn

Solve

t + \frac{π}{4} = \frac{π}{6} + 2 πn : t = 2 πn - \frac{π}{12}

Solve

t + \frac{π}{4} = \frac{5 π}{6} + 2 πn : t = 2 πn + \frac{7 π}{12}

t = 2 πn - \frac{π}{12}, t = 2 πn + \frac{7 π}{12}

Solutions for the range

π \leq t \leq \frac{7 π}{2}

t = \frac{23 π}{12}, t = \frac{31 π}{12}

tan (x) = 3007

2 sin (θ) - 3 = 0

2 cos^{2} (t) + 7 cos (t) + 5 = 0

cos (x) = \frac{35}{45}

\frac{π}{6} = cos (2 t)

What is the general solution for sin(t+pi/4)= 1/2 ,pi<= t<= (7pi)/2 ?
The general solution for sin(t+pi/4)= 1/2 ,pi<= t<= (7pi)/2 is t=(23pi)/(12),t=(31pi)/(12)