What is the general solution for tan^3(θ)=tan(θ) ?

The general solution for tan^3(θ)=tan(θ) is θ=pin,θ=(3pi)/4+pin,θ= pi/4+pin

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tan^3(θ)=tan(θ)

tan^{3} (θ) = tan (θ)

θ = πn, θ = \frac{3 π}{4} + πn, θ = \frac{π}{4} + πn

Solution steps

tan^{3} (θ) = tan (θ)

Solve by substitution

tan (θ) = 0, tan (θ) = - 1, tan (θ) = 1

tan (θ) = 0 : θ = πn

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

tan (θ) = 1 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = πn, θ = \frac{3 π}{4} + πn, θ = \frac{π}{4} + πn

arcsin (2 x) + arcsin (x) = \frac{2 π}{3}

2 sin (4 x) + 8 = 0

sin (x - 53.1 3^{\circ}) = - \frac{2}{5}

2 csc (x) + 2 = 0

1 + cos (x) = 3 cos (x)

What is the general solution for tan^3(θ)=tan(θ) ?
The general solution for tan^3(θ)=tan(θ) is θ=pin,θ=(3pi)/4+pin,θ= pi/4+pin