What is the general solution for (cos(x))(bsin(x)-a)=0,0<= x<2pi ?

The general solution for (cos(x))(bsin(x)-a)=0,0<= x<2pi is x= pi/2 ,x=(3pi)/2

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(cos(x))(bsin(x)-a)=0,0<= x<2pi

(cos (x)) (b sin (x) - a) = 0, 0 \leq x < 2 π

x = \frac{π}{2}, x = \frac{3 π}{2}

Solution steps

(cos (x)) (b sin (x) - a) = 0, 0 \leq x < 2 π

Solving each part separately

cos (x) = 0 or b sin (x) - a = 0

cos (x) = 0, 0 \leq x < 2 π : x = \frac{π}{2}, x = \frac{3 π}{2}

b sin (x) - a = 0, 0 \leq x < 2 π :

No Solution

Combine all the solutions

x = \frac{π}{2}, x = \frac{3 π}{2}

cos (x) = - \frac{5}{34}

sin (3 x) = \frac{1}{2}, 0 \leq x \leq 1

sec (θ) = - \frac{1}{2}

cos (x) = cos (x - c)

4 cos (120 t) = 0

What is the general solution for (cos(x))(bsin(x)-a)=0,0<= x<2pi ?
The general solution for (cos(x))(bsin(x)-a)=0,0<= x<2pi is x= pi/2 ,x=(3pi)/2