What is the general solution for 4cos(120t)=0 ?

The general solution for 4cos(120t)=0 is t= pi/(240)+(pin)/(60),t= pi/(80)+(pin)/(60)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4cos(120t)=0

4 cos (120 t) = 0

t = \frac{π}{240} + \frac{πn}{60}, t = \frac{π}{80} + \frac{πn}{60}

Solution steps

4 cos (120 t) = 0

Divide both sides by

4

cos (120 t) = 0

General solutions for

cos (120 t) = 0

120 t = \frac{π}{2} + 2 πn, 120 t = \frac{3 π}{2} + 2 πn

Solve

120 t = \frac{π}{2} + 2 πn : t = \frac{π}{240} + \frac{πn}{60}

Solve

120 t = \frac{3 π}{2} + 2 πn : t = \frac{π}{80} + \frac{πn}{60}

t = \frac{π}{240} + \frac{πn}{60}, t = \frac{π}{80} + \frac{πn}{60}

\frac{3 3}{π} = sec (c)

2 \cdot sin^{2} (x) = sin (x)

tan (x) = \frac{1}{3}

sin (x) sin (2 x) - 2 cos (x) cos (2 x) = 0

a, y = sin (a)

What is the general solution for 4cos(120t)=0 ?
The general solution for 4cos(120t)=0 is t= pi/(240)+(pin)/(60),t= pi/(80)+(pin)/(60)