What is the general solution for 2*sin^2(x)=sin(x) ?

The general solution for 2*sin^2(x)=sin(x) is x= pi/6+2pin,x=(5pi)/6+2pin,x=2pin,x=pi+2pin

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2*sin^2(x)=sin(x)

2 \cdot sin^{2} (x) = sin (x)

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

2 sin^{2} (x) = sin (x)

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = 0

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = 2 πn, x = π + 2 πn

tan (x) = \frac{1}{3}

sin (x) sin (2 x) - 2 cos (x) cos (2 x) = 0

a, y = sin (a)

cot^{2} (x) + csc (x) + 1 = 0

csc (θ) = 1.7824

What is the general solution for 2*sin^2(x)=sin(x) ?
The general solution for 2*sin^2(x)=sin(x) is x= pi/6+2pin,x=(5pi)/6+2pin,x=2pin,x=pi+2pin