What is the general solution for sin(u)-2sin(u)cos(u)=0 ?

The general solution for sin(u)-2sin(u)cos(u)=0 is u=2pin,u=pi+2pin,u= pi/3+2pin,u=(5pi)/3+2pin

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sin(u)-2sin(u)cos(u)=0

sin (u) - 2 sin (u) cos (u) = 0

u = 2 πn, u = π + 2 πn, u = \frac{π}{3} + 2 πn, u = \frac{5 π}{3} + 2 πn

Solution steps

sin (u) - 2 sin (u) cos (u) = 0

Factor

sin (u) - 2 sin (u) cos (u) : - sin (u) (2 cos (u) - 1)

- sin (u) (2 cos (u) - 1) = 0

Solving each part separately

sin (u) = 0 or 2 cos (u) - 1 = 0

sin (u) = 0 : u = 2 πn, u = π + 2 πn

2 cos (u) - 1 = 0 : u = \frac{π}{3} + 2 πn, u = \frac{5 π}{3} + 2 πn

Combine all the solutions

u = 2 πn, u = π + 2 πn, u = \frac{π}{3} + 2 πn, u = \frac{5 π}{3} + 2 πn

20 = 27 sin (x) - 1.5 cos (x)

- 3 sin (θ) = 0

\frac{cos ( x )}{sin ( x )} = 1

- 2 tan (θ) - 4 - tan^{2} (θ) = - 3

cos^{2} (x) = 3 - 5 cos (x)

What is the general solution for sin(u)-2sin(u)cos(u)=0 ?
The general solution for sin(u)-2sin(u)cos(u)=0 is u=2pin,u=pi+2pin,u= pi/3+2pin,u=(5pi)/3+2pin