What is the general solution for tan(θ)=-0.5586,0<= θ<2pi ?

The general solution for tan(θ)=-0.5586,0<= θ<2pi is θ=-0.50942…+pi,θ=5.77376…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(θ)=-0.5586,0<= θ<2pi

tan (θ) = - 0.5586, 0 \leq θ < 2 π

θ = - 0.50942 \dots + π, θ = 5.77376 \dots

Solution steps

tan (θ) = - 0.5586, 0 \leq θ < 2 π

Apply trig inverse properties

θ = arctan (- 0.5586) + πn

Solutions for the range

0 \leq θ < 2 π

θ = - 0.50942 \dots + π, θ = 5.77376 \dots

6 cos^{2} (x) - sin (x) - 5 = 0, 0 \leq x \leq 2 π

sin (4 x) = sin (3 x)

4 cos (x) + 3 = 5

sec (θ) = cos (θ)

x, sin (x) + 1 = 0

What is the general solution for tan(θ)=-0.5586,0<= θ<2pi ?
The general solution for tan(θ)=-0.5586,0<= θ<2pi is θ=-0.50942…+pi,θ=5.77376…