What is the general solution for solvefor x,sin(x)+1=0 ?

The general solution for solvefor x,sin(x)+1=0 is x=(3pi)/2+2pin

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solvefor x,sin(x)+1=0

solve for

x, sin (x) + 1 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

sin (x) + 1 = 0

Move

1

to the right side

sin (x) = - 1

General solutions for

sin (x) = - 1

x = \frac{3 π}{2} + 2 πn

\frac{8}{sin ( 3 8 ^{\circ} )} = \frac{6}{sin ( a )}

28 cos (θ) = 4, 0^{\circ} \leq θ < 36 0^{\circ}

6 sin (θ) + 2 = sin (θ)

cos (θ) = - \frac{19}{17}

5 = 7 - cos (θ) + 5 cos (2 θ)

What is the general solution for solvefor x,sin(x)+1=0 ?
The general solution for solvefor x,sin(x)+1=0 is x=(3pi)/2+2pin