What is the general solution for 8sin^2(x)-1=5 ?

The general solution for 8sin^2(x)-1=5 is x= pi/3+2pin,x=(2pi)/3+2pin,x=(4pi)/3+2pin,x=(5pi)/3+2pin

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8sin^2(x)-1=5

8 sin^{2} (x) - 1 = 5

x = \frac{π}{3} + 2 πn, x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

8 sin^{2} (x) - 1 = 5

Solve by substitution

sin (x) = \frac{3}{2}, sin (x) = - \frac{3}{2}

sin (x) = \frac{3}{2} : x = \frac{π}{3} + 2 πn, x = \frac{2 π}{3} + 2 πn

sin (x) = - \frac{3}{2} : x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

sin (d) = 0.8

csc (θ) = \frac{17}{8}

\frac{π}{3} cos (\frac{π x}{6}) = 0, x

cos (θ) = \frac{4}{3.92739}

sin (x) + sin (\frac{π}{2} - x) = 0

What is the general solution for 8sin^2(x)-1=5 ?
The general solution for 8sin^2(x)-1=5 is x= pi/3+2pin,x=(2pi)/3+2pin,x=(4pi)/3+2pin,x=(5pi)/3+2pin