What is the general solution for (-1/4)+cos^2(x)=1 ?

The general solution for (-1/4)+cos^2(x)=1 is No Solution for x\in\mathbb{R}

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(-1/4)+cos^2(x)=1

(- \frac{1}{4}) + cos^{2} (x) = 1

No Solution for x \in R

Solution steps

(- \frac{1}{4}) + cos^{2} (x) = 1

Solve by substitution

cos (x) = \frac{5}{2}, cos (x) = - \frac{5}{2}

cos (x) = \frac{5}{2} :

No Solution

cos (x) = - \frac{5}{2} :

No Solution

Combine all the solutions

No Solution for x \in R

x, e^{s i n (x)} = e^{- s i n (x)}

\frac{cos ( x )}{sin ( x )} = tan (x)

sin (B) = \frac{7 sin ( 3 6 ^{\circ} )}{12}

x, cos^{2} (x) = sin (y + \frac{π}{2})

0 = (sin (x))^{2}

What is the general solution for (-1/4)+cos^2(x)=1 ?
The general solution for (-1/4)+cos^2(x)=1 is No Solution for x\in\mathbb{R}