What is the general solution for cos(b)=0.47 ?

The general solution for cos(b)=0.47 is b=1.08150…+2pin,b=2pi-1.08150…+2pin

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cos(b)=0.47

cos (b) = 0.47

b = 1.08150 \dots + 2 πn, b = 2 π - 1.08150 \dots + 2 πn

Solution steps

cos (b) = 0.47

Apply trig inverse properties

b = arccos (0.47) + 2 πn, b = 2 π - arccos (0.47) + 2 πn

Show solutions in decimal form

b = 1.08150 \dots + 2 πn, b = 2 π - 1.08150 \dots + 2 πn

- 6 = - 5 + cos (θ)

tan (x) = - 26, \frac{3 π}{2} < x < 2 π

- sin^{2} (x) + cos^{2} (x) = 1

tan^{2} (x) - 4 sec (x) = 4

sin (x + 1 0^{\circ}) = - tan (1 5^{\circ})

What is the general solution for cos(b)=0.47 ?
The general solution for cos(b)=0.47 is b=1.08150…+2pin,b=2pi-1.08150…+2pin