What is the general solution for 2cos^2(x)+cos(x)=cos(2x) ?

The general solution for 2cos^2(x)+cos(x)=cos(2x) is x=pi+2pin

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2cos^2(x)+cos(x)=cos(2x)

2 cos^{2} (x) + cos (x) = cos (2 x)

x = π + 2 πn

Solution steps

2 cos^{2} (x) + cos (x) = cos (2 x)

Subtract

cos (2 x)

from both sides

2 cos^{2} (x) + cos (x) - cos (2 x) = 0

Rewrite using trig identities

cos (x) + 1 = 0

Move

1

to the right side

cos (x) = - 1

General solutions for

cos (x) = - 1

x = π + 2 πn

tan (x) - tan (\frac{π}{18}) = 1 + tan (x) tan (\frac{π}{18})

cos (θ) = \frac{2}{5}, cot (θ) < 0

θ, cos (θ) = \frac{2}{2}

b, s (t) = tan (b t^{2})

tan (x) = \frac{80}{90}

What is the general solution for 2cos^2(x)+cos(x)=cos(2x) ?
The general solution for 2cos^2(x)+cos(x)=cos(2x) is x=pi+2pin