What is the general solution for tanh(x)=0.99 ?

The general solution for tanh(x)=0.99 is x= 1/2 ln(199)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tanh(x)=0.99

tanh (x) = 0.99

x = \frac{1}{2} ln (199)

Solution steps

tanh (x) = 0.99

Rewrite using trig identities

\frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}} = 0.99

\frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}} = 0.99 : x = \frac{1}{2} ln (199)

x = \frac{1}{2} ln (199)

3 cos (3 0^{\circ}) + 4 cos (y) = 3

tan (y) = \frac{6}{4}

cos (x) = \frac{- 1 + 5}{4}

t, a = 5 \cdot sin (t)

cos^{(2)} (x) = \frac{( 3 ( 1 - sin ( x ) ) )}{( 2 )}

What is the general solution for tanh(x)=0.99 ?
The general solution for tanh(x)=0.99 is x= 1/2 ln(199)